给定两个非空链表来表示两个非负整数。位数按照逆序方式存储,它们的每个节点只存储单个数字。将两数相加返回一个新的链表。
你可以假设除了数字 0 之外,这两个数字都不会以零开头。
示例:
输入:(2 -> 4 -> 3) + (5 -> 6 -> 4)
输出:7 -> 0 -> 8
原因:342 + 465 = 807
# Definition for singly-linked list.
# class ListNode:
# def __init__(self, x):
# self.val = x
# self.next = None
class Solution:
def addTwoNumbers(self, l1, l2):
"""
:type l1: ListNode
:type l2: ListNode
:rtype: ListNode
"""
carry = 0
isFirst = True
currentNode = None
head = None
while(l1 or l2 or carry != 0):
val1 = 0
val2 = 0
if l1:
val1 = l1.val
l1 = l1.next
if l2:
val2 = l2.val
l2 = l2.next
sum = val1 + val2 + carry
if sum >= 10:
carry = 1
sum = sum % 10
else:
carry = 0
node = ListNode(sum)
if isFirst:
currentNode = node
head = currentNode
isFirst = False
else:
currentNode.next = node
currentNode = currentNode.next
return head
如果觉得《python两个数相加时_两数相加 leetcode Python》对你有帮助,请点赞、收藏,并留下你的观点哦!